In a right angle triangle ABC, right angled at B, BC = 12 cm and AB = 5 cm. The radius of the circle inscribed in the triangle (in cm) is
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Given:
– AB = 5 cm, BC = 12 cm, AC = 13 cm (using Pythagoras theorem).
Radius of incircle:
r = (a + b – c) / 2,
where a = 5, b = 12, c = 13.
Substitute:
r = (5 + 12 – 13) / 2 = 4 / 2 = 2 cm.
This question related to Chapter 10 Mathematics Class 10th NCERT. From the Chapter 10 Circle. Give answer according to your understanding.
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