Bhavani das
  • 2

In a reaction, 5.3 g of sodium carbonate reacted with 6 g of ethanoic acid. The products were 2.2 g of carbon dioxide, 0.9 g water and 8.2 g of sodium ethanoate. Show that these observations are in agreement with the law of conservation of mass.

  • 2

Class9, Science, NCERT, CBSE, 2022-2023, Chapter 2, Atoms And Molecules,

NCERT Solutions for Class 9 Science Chapter 3
Atoms And Molecules
NCERT Books for Session 2022-2023
CBSE Board and UP Board
Intext Questions
Page No-33
Questions No-1

sodium carbonate + ethanoic acid → sodium ethanoate + carbon dioxide + water

Share

2 Answers

  1. In a reaction, sodium carbonate reacts with ethanoic acid to produce sodium ethanoate,
    carbondioxide, and water.

    Sodium + Ethanoic → Sodium + Carbon + Water
    Carbonate acid ethanoate dioxide

    Mass of sodium carbonate = 5.3g (Given)
    Mass of ethanoic acid = 6g (Given)
    Mass of sodium ethanoate = 8.2g (Given)
    Mass of carbon dioxide = 2.2 (Given)
    Mass of water = 0.9g (Given)

    Now, total mass before the reaction = (5.3 + 6)g
    = 11. 3g
    and total mass after the reaction = (8.2 + 2.2 + 0.9)g
    = 11.3g
    Therefore, Total mass before the reaction = Total mass after the reaction
    Hence, the given observations are in agreement with the law of conservation of mass.

    For more answers visit to website:
    https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-3/

    • 1
  2. Reaction Description:
    In this reaction, sodium carbonate reacts with ethanoic acid to produce sodium ethanoate, carbon dioxide, and water.

    The equation can be represented as follows:
    Na2CO3 + 2CH3COOH → 2 CH3COONa + CO2 + H2O

    Given Information:
    – Mass of sodium carbonate (Na2CO3) = 5.3g
    – Mass of ethanoic acid (CH3COOH) = 6g
    – Mass of sodium ethanoate (CH3COONa) = 8.2g
    – Mass of carbon dioxide (CO2) = 2.2g
    – Mass of water (H2O) = 0.9g

    Analysis:
    1. Total Mass before the Reaction:
    – Mass of sodium carbonate + Mass of ethanoic acid = 5.3g + 6g = 11.3g

    2. Total Mass after the Reaction:
    – Mass of sodium ethanoate + Mass of carbon dioxide + Mass of water = 8.2g + 2.2g + 0.9g = 11.3g

    Conclusion:
    The total mass before the reaction matches the total mass after the reaction, both equaling 11.3 grams. This observation aligns perfectly with the law of conservation of mass.

    Explanation:
    – Conservation of Mass Principle: This law states that in any chemical reaction, the total mass of the substances before the reaction is equal to the total mass of the substances after the reaction.

    – Observation Comparison:
    – Before Reaction:
    – Mass of sodium carbonate + Mass of ethanoic acid = 5.3g + 6g = 11.3g
    – After Reaction:
    – Mass of sodium ethanoate + Mass of carbon dioxide + Mass of water = 8.2g + 2.2g + 0.9g = 11.3g

    – Equality in Mass:
    – The total mass before the reaction matches the total mass after the reaction, both being 11.3 grams.

    – Implication:
    – This correspondence confirms that no mass is either lost or gained during the chemical reaction between sodium carbonate and ethanoic acid.

    – Conclusion:
    – The given observations align perfectly with the law of conservation of mass, demonstrating that mass remains constant in a chemical reaction, affirming a fundamental principle in chemistry.

    • 0
Leave an answer

Leave an answer

Browse