In a laboratory, the count of bacteria in a certain experiment was increasing at the rate of 2.5% per hour. Find the bacteria at the end of 2 hours if the count was initially 5,06,000.

Here, Principal (P) = 5,06,000, Rate of Interest (R) = 2.5%, Time (n) = 2 hours
After 2 hours, number of bacteria,
Amount (A) =P(1+R/100)ⁿ
= 506000(1+ 2.5/100)²
= 506000(1+ 25/100)²
= 506000(1+ 25/40)²
= 506000(41/40)²
= 506000 x 41/40 x 41/40 = 5,31,616.25
Hence, number of bacteria after two hours are 531616 (approx.).

Class 8 Maths Chapter 8 Exercise 8.3 Solution in Video

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