If z = 1 – cos 2 θ + i sin 2 θ, then ∣ z ∣
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Choice (c) is correct.
Here, z = 1 – cos 2 θ + i sin 2 θ
∣ z ∣ = ∣1 – cos 2 θ + i sin 2 θ∣ = √(1 – cos 2θ)² + (sin 2θ)²
= √ 1 -2 cos 2 θ + sin² 2θ = √1 – 2 cos2θ + 1
= √2 -2 cos 2 θ = √2(1- cos 2θ ) = √2(2 sin² θ) = 2 ∣ sin θ ∣
This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding.
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