NCERT Solutions for Class 10 Maths Chapter 2

Important NCERT Questions

Polynomials

NCERT Books for Session 2022-2023

CBSE Board and UP Board Others state Board

EXERCISE 2.4

Page No:36

Questions No:1 Part:3

# If the zeroes of the polynomial x³ – 3 x² + x + 1 are a – b, a, a + b, find a and b.

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We know that,

Sum of zeroes = -(Cofficient of x²)/Cofficient of x³)

Therefore,

(a – b) + a + (a + b) = (-(-3))/1

⇒ 3a = 3

⇒ a = 1

Product of zeroes = -(Constant term)/(Cofficient of x³)

Therefore,

(a – b)(a)(a + b) = -(1)/1

⇒ (1 – b)1(1 + b) = -1 [Because a = 1]

⇒ 1 – b² = – 1

⇒ b² = 2

⇒ b = +- √2

Hence, a = 1 and b = +- √2

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