If the volume of a right circular cone of height 9 cm is 48 π cm³, find the diameter of its base.

Volume of cone V = 48π cm³ and height h = 9 cm
Let, the radius of base of cone = r cm
Volume of cone = 1/3πr²h
⇒ 48π = 1/3 × π × r² × 9 ⇒ 48π = π × r² × 3 ⇒ r² = 48π/π×3 = 16 ⇒ r = √16 = 4 cm
Therefore, the diameter of base = 2 × 4 = 8 cm
Hence, the diameter of base of cone is 8 cm.