NCERT Solutions for Class 10 Maths Chapter 8
Important NCERT Questions
Introduction Trigonometry
NCERT Books for Session 2022-2023
CBSE Board and UP Board Others state Board
EXERCISE 8.2
Page No:187
Questions No:3
If tan (A + B) = √3 and tan (A – B) = 1/√3 ; 0° B, find A and B.
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Given that: tan(A + B) = √3
⇒ tan (A+B) = tan 60° [∵ tan 60° = √3]
⇒ A+B= 60° …(i)
Given that: tan (A – B) = 1/√3
⇒ tan(A-B) = tan 30° [∵ tan 30° = 1/√3]
⇒ A-B = 30° …(ii)
Solving the equations (i) and (ii), we get
2A = 90° ⇒ A = 45°
From equation (1), we get
45°+B = 60° ⇒ B = 15°
Hence, A = 45° and B = 15°
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