If a pole 6m high casts a shadow 2√3m long on the ground, then sun’s elevation is
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We are given:
– Height of the pole = 6m,
– Length of the shadow = 2√3m.
The angle of elevation (θ) of the sun can be found using the tangent function:
tanθ = (Height of the pole) / (Length of the shadow).
Substitute the values:
tanθ = 6 / (2√3).
Simplify:
tanθ = 3 / √3 = √3.
From trigonometric values, tanθ = √3 corresponds to θ = 60°.
This question related to Chapter 9 Mathematics Class 10th NCERT. From the Chapter 9 Applications of Trigonometry. Give answer according to your understanding.
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