Jay Singh
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Given sec θ = 13/12, Calculate all other trigonometric ratios.

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NCERT Solutions for Class 10 Maths Chapter 8
Important NCERT Questions
Introduction Trigonometry
NCERT Books for Session 2022-2023
CBSE Board and UP Board Others state Board
EXERCISE 8.1
Page No:181
Questions No:5

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2 Answers

  1. Given that: sec 0 = 13/12
    Let sec 0 = 13k/12k, where k is a real number.
    In △ABC, by Pythagoras theorem, we have
    BC² = AC² – AB²
    = (13k)² – (12k)²
    = 169k² 144k²
    = 25k²
    ⇒ BC = √(25k²) = 5k
    Hence, sin 0 = BC/AC = 5k/13k = 5/13
    cos 0 = AB/AC = 12k/13k = 12/13
    tan 0 = BC/AB = 5k/12k = 5/12
    cose 0 = AC/BC = 13k/5k = 13/5 and cot 0 = AB/BC = 12k/5k = 12/5

    See the below video for better explanation of the above question👇😀

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  2. Get Hindi Medium and English Medium NCERT Solution for Class 10 Maths to download.
    Please follow the link to visit website for first and second term exams solutions.
    https://www.tiwariacademy.com/ncert-solutions/class-10/maths/chapter-8/

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