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Given 125² = 15625, what is the value of 126²? (i) 15625 + 126 (ii) 15625 + 26² (iii) 15625 + 251 (iv) 15625 + 253 (v) 15625 + 51²

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Using the identity (a+1)² = a² + 2a + 1,
126² = 125² + 2×125 + 1 = 15625 + 250 + 1 = 15625 + 251.
So, the correct option is (iv) 15625 + 251.

Class 8 NCERT Ganita Prakash Chapter 1 A Square and A Cube solutions

Class 8 Mathematics Textbook Chapter 1 A Square and A Cube question answer

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1 Answer

  1. To find 126² using 125², apply the identity:
    (a+1)² = a² + 2a + 1
    Here, a = 125, so
    126² = 125² + 2×125 + 1 = 15625 + 250 + 1 = 15625 + 251
    Therefore, the correct option is (iv) 15625 + 251. This method allows quick calculations using known square values and avoids complete re-multiplication.

     

    For more NCERT Solutions for Class 8 Mathematics Ganita Prakash Chapter 1 A Square and A Cube Extra Questions & Answer:

    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/ganita-prakash-chapter-1/

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