Using the identity (a+1)² = a² + 2a + 1,
126² = 125² + 2×125 + 1 = 15625 + 250 + 1 = 15625 + 251.
So, the correct option is (iv) 15625 + 251.
Class 8 NCERT Ganita Prakash Chapter 1 A Square and A Cube solutions
Class 8 Mathematics Textbook Chapter 1 A Square and A Cube question answer
To find 126² using 125², apply the identity:
(a+1)² = a² + 2a + 1
Here, a = 125, so
126² = 125² + 2×125 + 1 = 15625 + 250 + 1 = 15625 + 251
Therefore, the correct option is (iv) 15625 + 251. This method allows quick calculations using known square values and avoids complete re-multiplication.
For more NCERT Solutions for Class 8 Mathematics Ganita Prakash Chapter 1 A Square and A Cube Extra Questions & Answer:
https://www.tiwariacademy.com/ncert-solutions/class-8/maths/ganita-prakash-chapter-1/