(i) S = {1H, 1T, 2H, 2T, 3H, 3T, 4H, 4T, 5H, 5T, 6H, 6T} with 12 outcomes.
(ii) S = {-4, -3, -2, -1, 0, 1, 2, 3, 4}.
(iii) By color, S = {Green, Red}; by distinct balls, S = {G1, G2, G3, G4, G5, R1, …, R7}.
For the following experiments write down the sample space S. (i) Rolling a die and tossing a coin together. (ii) Choosing a random integer between – 5 and + 5. (iii) A box containing 5 green and 7 red balls. One ball is drawn at random.
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(i) Die gives {1, 2, 3, 4, 5, 6} and coin gives {H, T}:
S = {1H, 1T, 2H, 2T, 3H, 3T, 4H, 4T, 5H, 5T, 6H, 6T}.
Size n(S) = 6 x 2 = 12.
(ii) The integers lying strictly between -5 and +5 are:
S = {-4, -3, -2, -1, 0, 1, 2, 3, 4}.
(iii) By outcome of color, the sample space is:
S = {Green, Red}.
If each ball is treated distinctly, S = {G1, G2, G3, G4, G5, R1, R2, R3, R4, R5, R6, R7}, where n(S) = 12.
For more NCERT Solutions of Class 9 Ganita Manjari Chapter 7 The Mathematics of Maybe: Introduction to Probability Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-7/