For each of the following numbers, find the smallest whole number by which it should be divided so as to get a perfect square. Also, find the square root of the square number so obtained: (i) 252 (ii) 2925 (iii) 396 (iv) 2645 (v) 2800 (vi) 1620

(i) 252 = 2 x 2 x 3 x 3 x 7
Here, prime factor 7 has no pair. Therefore 252 must be
divided by 7 to make it a perfect square.
∴ 252 ÷ 7 = 36
And √36 = 2 x 3 = 6

(ii) 2925 = 3 x 3 x 5 x 5 x 13
Here, prime factor 13 has no pair.
Therefore 2925 must be divided by 13
to make it a perfect square.
∴ 2925 ÷ 13 = 225
And √225 = 3 x 5 = 15

(iii) 396 = 2 x 2 x 3 x 3 x 11
Here, prime factor 11 has no pair. Therefore 396 must be
divided by 11 to make it a perfect square.
∴ 396 ÷ 11 = 36
And √36 = 2 x 3 = 6

(iv) 2645 = 5 x 23 x 23
Here, prime factor 5 has no pair. Therefore 2645 must be
divided by 5 to make it a perfect square.
∴ 2645 ÷ 5 = 529
And √529 = 23 x 23 = 23

(v) 2800 = 2 x 2 x 2 x 2 x 5 x 5 x 7
Here, prime factor 7 has no pair. Therefore 2800 must be
divided by 7 to make it a perfect square.
∴ 2800 ÷ 7 = 400
And √400 = 2 x 2 x 5 = 20

Class 8 Maths Chapter 6 Exercise 6.3 Solution in Video

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