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Virat
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Asked: 2026-09-30T07:13:24+00:00 In:

Find two solutions which lie in different quadrants for the linear equation -5x – 3y = 7 and identify the quadrants.

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For x = -2, y = 1, giving (-2, 1) in Quadrant II. For x = 1, y = -4, giving (1, -4) in Quadrant IV. Both points satisfy -5x – 3y = 7.

class 9 maths ganita manjari part 2 chapter 13 question answer
Ganita Manjari Part 2 chapter 13 Two Variables, One Line solutions

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    1. Setting x = -2 in -5x – 3y = 7 gives 10 – 3y = 7, which simplifies to -3y = -3, yielding y = 1. The resulting point (-2, 1) lies in Quadrant II. Setting x = 1 produces -5 – 3y = 7, which simplifies to -3y = 12, yielding y = -4. The resulting point (1, -4) lies in Quadrant IV.

       

      For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 13 Two Variables, One Line Question Answer (2026-27)

      https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-13/

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