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Virat
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Asked: 2026-09-30T07:13:21+00:00 In:

Find two solutions which lie in different quadrants for the linear equation -5x + 3y = 7 and identify the quadrants.

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For x = 1, y = 4, giving (1, 4) in Quadrant I. For x = -2, y = -1, giving (-2, -1) in Quadrant III. Both points satisfy -5x + 3y = 7.

Cbse released Class 9 Ganita Manjari Part 2 book
Chapter 13 Two Variables, One Line (Ganita Manjari 2) Solutions

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    1. Substituting x = 1 into -5x + 3y = 7 produces -5 + 3y = 7, which simplifies to 3y = 12, giving y = 4. This corresponds to (1, 4) in Quadrant I. Substituting x = -2 gives 10 + 3y = 7, which simplifies to 3y = -3, yielding y = -1. This corresponds to the point (-2, -1) located in Quadrant III.

       

      For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 13 Two Variables, One Line Question Answer (2026-27)

      https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-13/

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