Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients. 6x² – 3 – 7x.

6x² – 3 – 7x
= 6x² – 7x – 3
= 6x² – 9x + 2x -3
= 3x(2x – 3) + 1(2x -3)
= (3x +1)(2x -3)
The value of 6x² – 7x – 3 is zero if 3x + 1 = 0 or 2x -3 = 0.
⇒ x = -1/3 or x = 3/2,
Therefore, the zeroes of 6x² – 7x – 3 are -1/3 and 3/2.
Now, Sum of zeroes = -1/3 + 3/2 = (-2 + 9)/6 = 7/6 = -(7)/6 = -(Cofficient of x)/Cofficient of x²
Product of zeroes = (-1/3) x 3/2 = -1/2 = (-3)/6 = Constant term/Cofficient of x².

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