Since, Exterior angle = Sum of interior opposite angles, therefore
(i) x + 50° = 115° ⇒ x = 115° – 50° = 65°
(ii) 70° + x = 100° ⇒ x = 100° – 70° = 30°
(iii) x + 90° = 125° ⇒ x = 120° – 90° = 35°
(iv) 60° + x = 120° ⇒ x = 120° – 60° = 60°
(v) 30° + x = 80° ⇒ x = 80° – 30° = 50°
(vi) x + 35° = 75° ⇒ x = 75° – 35° = 40°

Class 7 Maths Chapter 6 Exercise 6.2

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