Find the squares of the following numbers: (i) 32 (ii) 35 (iii) 86 (iv) 93 (v) 71 (vi) 46

(i) (32)² = (30+2)² = (30)² +2x30x2+(2)² [∵ (a+b)²=a²+2ab+b²]
= 900+120+4=1024
(ii) (35)² =(30+5)² =(30)² +2x30x5+(5)² [∵ (a+b)²=a²+2ab+b²]
= 900+300+25=1225
(iii) (86)²= (80+6)² =(80)² +2x80x6+(6)² [∵ (a+b)²=a²+2ab+b²]
=1600+960+36=1386
(iv) (93)² =(90+3)² =(90)² +2x90x3+(3)² [∵ (a+b)²=a²+2ab+b²]
= 8100+540+9=8649
(v) (71)² = (70+1)² =(70)² +2x70x1+(1)² [∵ (a+b)²=a²+2ab+b²]
= 4900+140+1=5041
(vi) (46)²=(40+6)² =(40)² +2x40x6+(6)² [∵ (a+b)²=a²+2ab+b²]
=1600+480+36=2216

Class 8 Maths Chapter 6 Exercise 6.2 Solution in Video

for more answers vist to:
https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-6/