L.C.M. of 8, 15 and 20 is 120.
Prime factors of 120 = 2 x 2 x 2 x 3 x 5
Here, prime factor 2, 3 and 5 has no pair. Therefore 120 must be
multiplied by
2 x 3 x 5 to make it a perfect square.
∴ 120x2x3x5 = 3600
Hence, the smallest square number which is divisible by 8, 15 and 20
is 3600.

Class 8 Maths Chapter 6 Exercise 6.3 Solution in Video

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https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-6/