NCERT Solutions for Class 8 Mathematics Chapter 6
Important NCERT Questions
Square and Square Roots Chapter 6 Exercise 6.3
NCERT Books for Session 2022-2023
CBSE Board
Questions No: 9
Find the smallest square number that is divisible by each of the numbers 4, 9 and 10.
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L.C.M. of 4, 9 and 10 is 180.
Prime factors of 180 = 2 x 2 x 3 x 3 x 5
Here, prime factor 5 has no pair. Therefore 180 must be multiplied
by 5 to make it a perfect square.
∴ 180 x 5 = 900
Hence, the smallest square number which is divisible by 4, 9 and 10
is 900.
Class 8 Maths Chapter 6 Exercise 6.3 Solution in Video
for more answers vist to:
https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-6/