Mayur Arya
  • -1

Find the smallest number that is a multiple of all the numbers from 1 to 10 except for 7.

  • -1

The number is 2520 ÷ 7 = 360. The least common multiple (LCM) of 1 to 10 is 2520. Excluding 7, we divide by 7 to obtain 360, the smallest valid number.

class 6 Mathematics Textbook Chapter 5 question answer

class 6 Mathematics Chapter 5 Prime Time solutions

Share

1 Answer

  1. The least common multiple (LCM) of all numbers from 1 to 10 is 2520, found by considering their prime factorizations. To exclude 7, divide 2520 by 7, yielding 360. This number is divisible by all integers from 1 to 10 except 7, satisfying the condition. The prime factorization of 360 further confirms this: 360 = 2 × 2 × 2 × 3 × 3 × 5, excluding 7 as a factor.

    For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
    https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/

    • 24
Leave an answer

Leave an answer

Browse