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Ayushree
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Asked: 2025-08-01T10:22:38+00:00 In:

Find the smallest number by which 9408 must be multiplied so that the product is a perfect square. Find the square root of the product.

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Prime factorise 9408: 2⁶ × 3 × 7 × 7. To make it a perfect square, we need another 3. Multiply by 3 → 9408 × 3 = 28224.
√28224 = 168. So, the smallest multiplier is 3.

Class 8 Mathematics Textbook Chapter 1 A Square and A Cube question answer

Class 8 Mathematics Chapter 1 A Square and A Cube solutions

class 8 mathematics new book all solution on tiwari academyclass 8 maths ganita prakash chapter 1 pdfsmallest number by which 9408 must be multiplied so that the product is a perfect square
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    1. Prime factorisation of 9408 = 2⁶ × 3 × 7². For a perfect square, all powers must be even. The factor 3 is unpaired. Multiply 9408 by 3 → 28224 = 2⁶ × 3² × 7². Now, all powers are even. √28224 = 2³ × 3 × 7 = 8 × 3 × 7 = 168.
      So, the smallest number to multiply is 3 and the square root of the result is 168.

       

      For more NCERT Solutions for Class 8 Mathematics Ganita Prakash Chapter 1 A Square and A Cube Extra Questions & Answer:

      https://www.tiwariacademy.com/ncert-solutions/class-8/maths/ganita-prakash-chapter-1/

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