In this sequence, the first term is 11 and common difference is -3. The explicit nth term simplifies to tn = 14 – 3n, while its recursive rule is stated as t1 = 11, tn = tn-1 – 3 for n > = 2.
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In this sequence, the first term is 11 and common difference is -3. The explicit nth term simplifies to tn = 14 – 3n, while its recursive rule is stated as t1 = 11, tn = tn-1 – 3 for n > = 2.
In the given sequence, the first term is a = 11 and the common difference is d = 8 – 11 = -3.
The explicit rule for the nth term is:
tn = a + (n – 1)d
tn = 11 + (n – 1) x (-3)
tn = 11 – 3n + 3
tn = 14 – 3n.
To write the recursive rule, each term after the first is obtained by adding the common difference:
t1 = 11 and tn = tn-1 – 3 for n >= 2.
For more NCERT Solutions of Class 9 Ganita Manjari Chapter 8 Predicting What Comes Next: Exploring Sequences and Progressions Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-8/