The value of the discriminant can be calculated by substituting the values of a, b, and c from the equation into the formula. Which is the value under the square root sign in the quadratic formula.
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NCERT Solutions for Class 10th Maths Chapter 4 EXERCISE 4.4 Questions No:1 Part (ii)
Find the nature of the roots of the following quadratic equations. If the real roots exist, find them: 3x² – 4√3 x + 4 = 0
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3x² – 4√3x + 4 = 0
The given equations is of the form ax² + bx + c = 0 in which a = 3, b = -4√3, c = 4
Therefore, D = b² – 4ac = (-4√3)² – 4 × 3 × 4 = 48 – 48 = 0
So, the roots of quadratic equation are real and equal.
Hence, x = 4√3±√0/6 = 4√3/6 = 2√3/3 [As x = -b±√b²-4ac]
Hence, the roots of the quadratic equation are 2√3/3 and 2√3/3.