The greatest 3-digit number divisible by 6, 9, and 12 is 972. It is a multiple of their least common multiple (LCM = 36) and is the largest number below 1000 divisible by 36.
class 6 Mathematics Textbook Chapter 5 question answer
class 6 Mathematics Chapter 5 Prime Time solutions
To find the greatest 3-digit number divisible by 6, 9, and 12, calculate their least common multiple (LCM):
• 6 = 2 × 3, 9 = 3², 12 = 2² × 3
• LCM = 2² × 3² = 36
Divide the largest 3-digit number, 999, by 36: 999 ÷ 36 = 27.75
Round down to 27, multiply: 27 × 36 = 972.
Thus, 972 is the largest 3-digit number divisible by 36.
For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/