Here Xc = 100Ω, v = 5/π kHz = 5000/π Hz
∴ C = 1/Xc . 2πv = 1/100 × 2π × 5000/π = 10-⁶F = 1µF.
Class 12 Physics Chapter 7 Alternating current Session 2024-2025.
Find the capacitance of the capacitor that would have a reactance of 100Ω when used with an a.c. source of frequency 5/π kHz.
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The capacitance of the capacitor can be calculated using the formula C = 1/Xc2πv
Given Xc =100Ω and v = 5000/π Hz, C =1/1002π 5000/π = 10-⁶ F = 1μF.
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