Anwesha Patel
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Find the area of the shaded region in Figure.

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If PQ = 24 cm, PR = 7 cm and O is the center of the circle.
NCERT class 10 Chapter 12 AREAS RELATED TO CIRCLES
Page No. 234
Exercise 12.3
Question No. 1

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1 Answer

  1. QR is diameter of circle.
    Therefore, ∠RPQ = 90° [Angle in semicircle is right angle]
    In APQR, by Pythagoras theorem,
    RP² + PQ² = RQ²
    (7)² + (24)² = RQ²
    ⇒ RQ² = 576 + 49 = 625
    ⇒ RQ = √625 = 25
    Therefore, the radius of circle = RQ/2 = 25/2 cm
    Area of shaded region = Area of semicircle – Area of APQR
    = 1/2 × πr² – 1/2 PR × PQ = 1/2 × π(25/2)² – 1/2 × 7 × 24 = 1/2 × 22/7 × 25/2 × 25/2 – 7 × 12
    = 6875/28 – 84 = (6875 – 2352)/28 = 4523/28 cm²

    Here is the video explanation ✌😇

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