Find the area of the quadrilateral whose vertices, taken in order, are (– 4, – 2), (– 3, – 5), (3, – 2) and (2, 3).

Area of triangle ABC
= 1/2 [(-4){-5(-2)}+(-3){-2-(-2)}+3{-2-(-5)}]
= 1/2 [12+0+9]
= 1/2 [21] = 10.5 square units
Area of triangle ACD
= 1/2 [(-4)(-2-3)+3{3-(-2)}+2{-2-2(-2)}]
= 1/2 [20+15+0] = 1/2[35] = 17.5 square units
Area of quadrilateral ABCD = Area of triangle ABC +Area of triangle ACD
⇒ Area of quadrilateral ABCD = (10.5+17.5) square units = 28 square units

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