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Reyansh
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Asked: 2020-10-30T03:18:24+00:00 In:

Find the area of the quadrilateral whose vertices, taken in order, are (– 4, – 2), (– 3, – 5), (3, – 2) and (2, 3).

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NCERT Solutions for Class 10 Maths Chapter 7
Important NCERT Questions
Coordinate Geometry
NCERT Books for Session 2022-2023
CBSE Board and UP Board Others state Board
EXERCISE 7.3
Page No:170
Questions No:4

2020-2021cbsechapter 7class10coordinate geometrymathematicsncert
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    1. Best Answer
      Find the area of the quadrilateral whose vertices, taken in order, are (– 4, – 2), (– 3, – 5), (3, – 2) and (2, 3).

      Area of triangle ABC
      = 1/2 [(-4){-5(-2)}+(-3){-2-(-2)}+3{-2-(-5)}]
      = 1/2 [12+0+9]
      = 1/2 [21] = 10.5 square units
      Area of triangle ACD
      = 1/2 [(-4)(-2-3)+3{3-(-2)}+2{-2-2(-2)}]
      = 1/2 [20+15+0] = 1/2[35] = 17.5 square units
      Area of quadrilateral ABCD = Area of triangle ABC +Area of triangle ACD
      ⇒ Area of quadrilateral ABCD = (10.5+17.5) square units = 28 square units

      See this Video Explanation😁

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    2. Get Hindi Medium and English Medium NCERT Solution for Class 10 Maths to download.
      Please follow the link to visit website for first and second term exams solutions.
      https://www.tiwariacademy.com/ncert-solutions/class-10/maths/chapter-7/

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