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Find the area of a triangle two sides of which are 18cm and 10cm and the perimeter is 42cm.

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NCERT Solutions for Class 9 Maths Chapter 12
Important NCERT Questions
Heron’s Formula
NCERT Books for Session 2022-2023
CBSE Board, UP Board and Other state Boards
EXERCISE 12.1
Page No:203
Questions No:4

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  1. Get Hindi Medium and English Medium NCERT Solution for Class 9 Maths to download.
    Please follow the link to visit website for first and second term exams solutions.
    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/chapter-12/

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  2. Here, the sides of triangle are a = 18 cm, b = 10 cm and primeter is 42 cm.
    We Know that the parimeter of triangle = a + b + c
    ⇒ 42 = 18 + 10 + c
    ⇒ c = 14 cm
    So, the semi- perimeter of triangle is given by
    S = a + b + c/2 = 42/2 = 21 cm
    Therefore, using Heron’s formula, the area of triangle = √s(s – a)(s – b)(s – c)
    = √21(21 – 18)(21 – 10)(21 – 14)
    = √21(3)(11)(7)
    = √7 × 3 × (3)(11)(7)
    = 7 × 3√11 = 21√11 cm²
    Hence, the area of triangle is 21√11 cm².

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