Circumference 2 x (22/7) x r = 44 yields radius r = 7 cm. A quadrant has angle 90°, so its area is (1/4) x π x r² = (1/4) x (22/7) x 7² = 77/2 = 38.5 cm².
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Given circumference of the circle = 44 cm.
Circumference = 2 x π x r = 44
2 x (22/7) x r = 44
(44/7) x r = 44, so r = 7 cm.
A quadrant is one-fourth of a circle (central angle θ = 90°).
Area of a quadrant = (1/4) x π x r²
= (1/4) x (22/7) x 7 x 7
= (1/4) x 154 = 77 / 2 = 38.5 cm².
Hence, the area of the quadrant is 38.5 cm².
For more NCERT Solutions of Class 9 Ganita Manjari Chapter 6 Measuring Space: Perimeter and Area Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-6/