Find the area of a quadrant of a circle whose circumference is 22 cm.

Let the radius of circle = r
Circumference = 22 cm
Therefore, 2πr = 22
⇒ r = 22/2π = 11/π
Quadrant of circle subtends an angle of 90° at the center.
Therefore, the area of quadrant
= 90°/360° × πr²
= 1/4 × π(11/π)² = 1/4 × π × 11/π = 121/4π = (121 × 7)/(4 × 22) = 77/8 cm²

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