For the given arithmetic progression, the first term is 3 and the common difference is 5. Using the formula tn = a + (n – 1)d, the 10th term is 48 and the 26th term is 128.
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In this arithmetic progression, the first term is a = 3 and the common difference is d = 8 – 3 = 5. The nth term of an AP is given by the formula tn = a + (n – 1)d. To find the 10th term, substitute n = 10: t10 = 3 + (10 – 1) x 5 = 3 + 9 x 5 = 3 + 45 = 48. To find the 26th term, substitute n = 26: t26 = 3 + (26 – 1) x 5 = 3 + 25 x 5 = 3 + 125 = 128. Thus, the terms are 48 and 128.
For more NCERT Solutions of Class 9 Ganita Manjari Chapter 8 Predicting What Comes Next: Exploring Sequences and Progressions Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-8/