NCERT Mathematics Class 9 chapter 1
Page No. 26
Exercise 1.6
Question No. 2
Find : (i) 9^(3/2) (ii)32^(2/5) (iii) 16^(3/4) (iv) 125^(-1/3)
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(i) 9^(3/2) = (3^2)^(3/2) = 3^(2×3/2) = 3^2 = 9
(ii) 32^(2/5) = (2^5)^(2/5) = 2^(5×2/5) = 2^2 = 4
(iii) 16^(3/4) = (2^4)^(3/2) = 2^(4×3/4) = 2^3 = 8
(iv) 125^(-1/3) = (5^3^(-1/3) = 5^(3×-1/3) = 5^-1 = 1/5 = 5