The polynomial matches the identity template a square – 2ab + b square. Since 16y square is (4y) square and 9 is (3) square, it condenses directly into (4y – 3) square.
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We look at the structure of this quadratic polynomial to find its factors. The first term 16y square is the square of 4y, and the constant term 9 is the square of 3. The middle term has a negative sign and is equal to minus two multiplied by 4y multiplied by 3, which equals minus 24y. This matches the subtraction identity perfectly, giving the factor (4y – 3) square.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 4 Exploring Algebraic Identities (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-4/