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Factor using suitable identities: 9/4 s square + 6st + 4t square

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This fits the identity a square + 2ab + b square. The first term is the square of 3/2 s and the last is the square of 2t, which yields the factor (3/2 s + 2t) square.

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  1. To factor this expression, we examine the perfect square parts at the ends. The first term 9/4 s square is equal to the quantity 3/2 s squared. The third term 4t square is equal to the quantity 2t squared. The middle term 6st is exactly equal to two times 3/2 s times 2t. This matches the standard addition identity, resulting in the factor (3/2 s + 2t) square.

     

    For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 4 Exploring Algebraic Identities (2026-27):

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-4/

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