keshav kumar
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Diagonal AC of a parallelogram ABCD bisects ∠A see Figure. Show that (i) it bisects ∠C also, (ii) ABCD is a rhombus.

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Prove the angle-angle-side congruence criterion.
What is implies rhombus.
Quadrilaterals Solutions for Class 9th Maths.
9th Maths EXERCISE 8.1,Page No:146, Questions No:6, Session 2023-2024.
Class 9th, NCERT Books for Session 2023-2024, based on CBSE Board.

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1 Answer

  1. (i) ∠DAC = ∠BAC …(1) [∵ Given]
    ∠DAC = ∠BCA …(2) [∵ Alternate angle]
    ∠BAC = ∠ACD …(3) [∵Alternate angles]
    From the equations (1), (2) and (3), we have
    ∠ACD = ∠BCA …(4)
    Hence, Diagonal AC bisects angle C also.
    (ii) From the equation (2) and (4), we have
    ∠ACD = ∠DAC
    In ΔADC,
    ∠ACD = ∠DAC [∵ Prove above]
    AD = DC [∵ In a triangle, the sides opposite to equal angle are equal]
    A parallelogram whose adjacent sides are equal, is a rhombus. Hence, ABCD is a rhombus.

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