Class 12 Physics
CBSE and UP Board
Electromagnetic Induction
Chapter-6 Exercise 6.8
NCERT Solutions for Class 12 Physics Chapter 6 Question 8
Current in a circuit falls from 5.0 A to 0.0 A in 0.1 s. If an average emf of 200 V induced, give an estimate of the self-inductance of the circuit
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Initial current, I₁= 5.0 A
Final current, I₂ = 0.0 A
Change in current, dl = I₁ — I2 = 5 A
Time taken for the change, t = 0.1 s
Average emf, e = 200 V
For self-inductance (L) of the coil, we have the relation for average emf as: e =di/dt
L = e/(di/dt)
=200/(5/0.1) = 4 H
Hence, the self-induction of the coil is 4 H.