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Garinder
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Asked: 2021-03-23T05:23:21+00:00 In:

Construct the right angled ∆PQR, where m∠Q = 90°, QR = 8 cm and PR = 10 cm.

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NCERT Solutions for Class 7 Mathematics Chapter 10
Important NCERT Questions
Class vii Math Chapter 10 Practical Geometry Exercise 10.5
NCERT Books for Session 2022-2023
CBSE Board
Questions No: 1

2020-2021cbsechapter 10class7mathematicsncertpractical geometry
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    1. Best Answer

      To construct:
      A right angled triangle PQR where m∠Q =90°, QR = 8 cm and PQ = 10 cm.
      Steps of construction:
      (a) Draw a line segment QR = 8 cm.
      (b) At point Q, draw QX ⊥QR.
      (c) Taking R as centre, draw an arc of radius 10 cm.
      (d) This arc cuts QX at point P.
      (e) Join PQ.
      It is the required right angled triangle PQR.

      Class 7 Maths Chapter 10 Exercise 10.5

      for more answers vist to:
      https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-10/

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