Construct the right angled ∆PQR, where m∠Q = 90°, QR = 8 cm and PR = 10 cm.

To construct:
A right angled triangle PQR where m∠Q =90°, QR = 8 cm and PQ = 10 cm.
Steps of construction:
(a) Draw a line segment QR = 8 cm.
(b) At point Q, draw QX ⊥QR.
(c) Taking R as centre, draw an arc of radius 10 cm.
(d) This arc cuts QX at point P.
(e) Join PQ.
It is the required right angled triangle PQR.

Class 7 Maths Chapter 10 Exercise 10.5

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