Rajiv Tyagi
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Construct the following angles and verify by measuring them by a protractor: (i) 75° (ii) 105° (iii) 135°

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NCERT Solutions for Class 9 Maths Chapter 11
Important NCERT Questions
Constructions
NCERT Books for Session 2022-2023
CBSE Board, UP Board and Other state Boards
EXERCISE 11.1
Page No:191
Questions No:4

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  1. Get Hindi Medium and English Medium NCERT Solution for Class 9 Maths to download.
    Please follow the link to visit website for first and second term exams solutions.
    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/chapter-11/

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  2. I/Steps of construction
    (i) Draw a ray AB at the point A.
    (ii) Taking A as centre and a convenient radius, draw an arc which intersect AB at C.
    (iii) Taking C as centre and with the same radius, draw an arc which intersect the previous arc at F.
    (iv) Similarly, taking E as centre and with the same radius, draw an arc which intersect at E.
    (v)Taking E and F as as center, draw arcs with equal radius (more than half of EF). which intersect at H.
    (vi) Draw a ray AH which intersects the main arc at D.
    (vii) Taking F and D as centre, draw arcs with equal radius (more than half of FD), which intersect at G.
    (viii) Draw a ray AG. ∠GAB is the required angle of 75°.

    II/Steps of construction.
    (i) Draw a ray AB at the point A.
    (II) Taking A as centre and a convenient radius, draw an arc which intersect AB at C.
    (iii) Taking C as center and with the same radius, Draw an arc which intersect the previous arc at D.
    (iv) Similarly, taking E as centre and with the equal radius, draw an arc which intersect at G.
    (v) Taking D and G as centre, draw arcs with same radius (more than half of DG), which intersect at F.
    (vi) Draw a ray AF which intersects the main arc at E.
    (vii) Taking E and G as centre, draw arcs with equal radius (more than half of EG), which intersect at H.
    (viii) Draw a ray AH. ∠HAB is the required angle of 105°.

    III/Steps of construction.
    (i) Draw a ray AD at the point A.
    (II) Taking B as centre and a convenient radius, draw an arc which intersect AD at C.
    (III) Taking C as centre and with the same radius, draw an arc which intersect the previous arc at P.
    (iv) Similarly, Taking P as centre and with the equal radius, draw an arc which intersect at F.
    (v) Taking P and F as centre, draw arcs with same radius (more than half of PF), which intersect at H.
    (vi) Draw a ray BH from the point B.
    (vii) Taking B as center, draw an arc taking some radius, which intersects AB at E and BH at Q.
    (viii) Taking E and Q as centre, draw arcs with equal radius (more than half of EQ), which intersect at G.
    (ix) Draw a ray BG. ∠GBD is the required angle of 135°.

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