Rajiv Tyagi
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Construct a triangle ABC in which BC = 8cm, ∠B = 45° and AB – AC = 3.5 cm.

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NCERT Solutions for Class 9 Maths Chapter 11
Important NCERT Questions
Constructions
NCERT Books for Session 2022-2023
CBSE Board, UP Board and Other state Boards
EXERCISE 11.2
Page No:195
Questions No:2

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  1. Get Hindi Medium and English Medium NCERT Solution for Class 9 Maths to download.
    Please follow the link to visit website for first and second term exams solutions.
    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/chapter-11/

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  2. Steps of construction
    (i) Draw a line segment BC = 8 cm.
    (ii) At point B, Using ruler and compass, draw an angle ∠CBX = 45°.
    (iii) Taking B as centre and radius 3.5 cm, mark an arc, which intersects AX at D.
    (iv) Jion CD and draw a perpendicular bisector (MN) of CD, which intersects at BD produced at A.
    (v) join AC.
    (vi) Triangle ABC is the required triangle.
    Justification
    Point A lies on the perpendicular bisector of DC. So, AD = AC
    Here, AB = BD – AD
    ⇒ AB = BD – AC [∵ AD = AC]

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