Compute the heat generated while transferring 96000 coulomb of charge in one hour through a potential difference of 50 V.

The heat (Q) generated when a charge (Q) moves through a potential difference (V) can be calculated using the formula:

Q = V. I. t

where:

» Q is the heat generated,
» V is the potential difference,
» I is the current, and
» t is the time.

The current (I) can be calculated using Ohm’s Law:

I = V/R

where:

» R is the resistance.
If we rearrange the formula for current and substitute it into the formula for heat, we get:

Q = V . v/R . t

Now, we need to know the resistance (R) to calculate the current. If the resistance is not provided, we cannot determine the exact amount of heat generated. However, if we assume that the circuit is purely resistive, we can use Ohm’s Law to find R as R = V/I.

Let’s proceed with this assumption:

R = V/I = V/V/R = R
So, in the case of a purely resistive circuit, R remains constant.
Now, substitute the values into the formula for heat:
Q = V . V/R . t

Q = V^2 t/R

Given:

V = 50 V
t = 1 hour = 3600 seconds
Assuming R is constant, we can calculate the heat generated using the provided potential difference and time:

Q = (50V)² 3600s/R

Please note that without information about the resistance (R), we cannot determine the actual heat generated. If you have the resistance value, you can substitute it into the formula to get the precise result.