Calculate the work required to be done to stop a car of 1500 kg moving at a velocity of 60 km/h?

Given:
– Mass of the car, m = 1500 kg
– Initial velocity of the car, v = 60 km/h

1. Convert Velocity to Meters per Second:
– Velocity in meters per second = (Velocity in km/h x 1000)/(3600)
– 60 km/h = (60 x 1000)/(3600} = 16.67 m/s

2. Calculate Initial Kinetic Energy:
– The kinetic energy (KE) of the car is given by KE = 1/2 m v² .
– Substitute the values:
KE = 1/2 x 1500 kg x (16.67 m/s²)
– KE = 208,333.33 J

3. Determine Work Required:
– The work (W) needed to stop the car is equal to the change in kinetic energy.
– W = Initial Kinetic Energy – Final Kinetic Energy)
– As the final kinetic energy is zero (when the car is brought to rest), ( W = 208,333.33 J – 0J = 208,333.33 J

Therefore, the work required to stop the car of 1500 kg moving at a velocity of 60 km/h is (208,333.33 J). This amount of work needs to be done to reduce the car’s kinetic energy to zero, bringing it to a complete stop.