NCERT Solutions for Class 9 Science Chapter 9
Force and Laws of Motion
NCERT Books for Session 2022-2023
CBSE Board and UP Board
Exercises Questions
Page No-129
Questions No-16
An object of mass 100 kg is accelerated uniformly from a velocity of 5 m s–1 to 8 m s–1 in 6 s. Calculate the initial and final momentum of the object. Also, find the magnitude of the force exerted on the object.
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Initial velocity of the object, u = 5 m/s
Final velocity of the object, v = 8 m/s
Mass of the object, m = 100 kg
Time take by the object to accelerate, t = 6 s
Initial momentum = mu = 100 × 5 = 500 kg ms ⁻¹
Final momentum = mv= 100 × 8 = 800 kg ms⁻¹
Force exerted on the object, 𝐹 = 𝑚𝑣−𝑚𝑢/𝑡
= m(v-u)/t = 800-500/6 = 300/6 = 50N
Initial momentum of the object is 500 kg ms⁻¹
.
Final momentum of the object is 800 kg ms-1.
Force exerted on the object is 50 N.
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