An object 5 cm in length is held 25 cm away from a converging lens of focal length 10 cm. Draw the ray diagram and find the position, size and the nature of the image formed.

Object distance, u = −25 cm
Object height, ho = 5 cm
Focal length, f = +10 cm
According to the lens formula,
1/v-1/u=1/f
1/v = 1/f + 1/u = 1/10 – 1/25 =15/250
V= 250/15 = 16.66 cm
The positive value of v shows that the image is formed at the other side of the lens.
Magnification,m = – Image Distance / Object Distance = – v/u = -16.66 / 25 = -0.66

The negative sign shows that the image is real and formed behind the lens.
Magnification,m = Image height / Object height = H₁ / H0 = H₁=5
H₁ = m X Ho = -0.66 X 5 = -3.3 cm
The negative value of image height indicates that the image formed is inverted.
The position, size, and nature of image are shown in the following ray diagram.

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