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Home/ Questions/Q 972
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Umangi Grover
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Umangi Grover
Asked: October 20, 20202020-10-20T11:54:31+00:00 2020-10-20T11:54:31+00:00In: Class 10

An electric heater of resistance 8 W draws 15 A from the service mains 2 hours. Calculate the rate at which heat is developed in the heater.

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NCERT Solution for Class 10 Science Chapter 12
Electricity
NCERT Books for Session 2022-2023
CBSE Board and UP Board
Exercises Questions
Page No-222
Questions No-17

2020-2021cbsechapter 12class10electricityncertscience
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    1. Consult From physics
      2020-12-06T07:01:09+00:00Added an answer on December 6, 2020 at 7:01 am

      Heat developed in the heater is given by H = I2Rt
      Where, I = 15 A, R = 8 Ω and time t = 2 hours
      The rate at which heat is developed is given by
      𝐻=𝐼²𝑅𝑡/𝑡=𝐼²𝑅=(15)²×8=1800 𝐽/𝑠

      For more answers visit to website:
      https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-12/

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    2. Praveen
      2021-02-03T09:13:01+00:00Added an answer on February 3, 2021 at 9:13 am

      Rate of heat produced by a device is given by the expression for power as

      P = I2R

      Where,

      Resistance of the electric heater, R = 8 Ω

      Current drawn, I = 15 A

      P = (15)2 x 8 = 1800 J/s

      Therefore, heat is produced by the heater at the rate of 1800 J/s.

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