An electric current of 5 A is passing through a circuit containing three wires arranged in para llel. If the lengths and radii of the wires are in the ratio 2: 3: 4 and 3: 4: 5, then the ratio of currents passing through wires should be
Resistance R of a wire is R = ρ (l / A) = ρ (l / πr²). Given l₁:l₂:l₃ = 2:3:4 and r₁:r₂:r₃ = 3:4:5, solving for I, the ratio is 54:64:75.
Answer: (b) 54:64:75.
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