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An artificial satellite is moving in a circular orbit of radius 42250 km. Calculate its speed if it takes 24 hours to revolve around the earth.

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NCERT Solutions for Class 9 Science Chapter 8
Motion
NCERT Books for Session 2022-2023
CBSE Board and UP Board
Exercises Questions
Page No-113
Questions No-10

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2 Answers

  1. Here,
    r = 42250 km = 42250000 m
    T = 24 h = 24 × 60 × 60 s
    Using Speed, v = 2πr ÷ T
    v = (2 × 3.14 × 42250000) ÷ (24 × 60 × 60) m/s
    = 3070.9 m/s = 3.07 km/s

    For more answers visit to website:
    https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-8/

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  2. To find the speed of the artificial satellite moving in a circular orbit around the Earth, we can use the formula relating the circumference of the orbit to the time taken for one revolution.

    The formula for the circumference of a circle is 2 x π x radius

    Given:
    – Radius of the orbit r = 42250 km
    – Time taken for one revolution T = 24 hours

    Calculations:
    The circumference of the circular orbit:
    Circumference = 2 x π x radius = 2 x π x 42250 km

    The speed of the satellite is given by the formula:
    Speed = Circumference / Time taken for one revolution

    First, let’s convert the time from hours to seconds because the speed is usually measured in distance per unit time in seconds.

    Given: 1 hour = 3600 seconds
    Time taken for one revolution in seconds = 24 hours 3600 seconds/hour = 86400 seconds

    Now, calculate the speed:
    Speed = (2 x π x 42250 km) / (86400 seconds)
    Speed ≈ (2 x 3.1416 x 42250 km) / (86400 seconds)
    Speed ≈ 265258 km) / (86400 seconds)
    Speed ≈ 3.07 km/s

    Therefore, the speed of the artificial satellite moving in a circular orbit of radius 42250 km, taking 24 hours to revolve around the Earth, is approximately 3.07 kilometers per second.

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