A wire of diameter 1 mm breaks under a tension 0f 1000 N. Another wire, of same material as that of the first one, but of diameter 2mm breaks under a tension of
Tension is the force exerted along a stretched object like a rope string or cable when it is pulled from opposite ends. It acts to restore the object to its original length and is directed along its length. Tension plays a key role in mechanics and structural applications.
Class 11 Physics Chapter 8 covers mechanical properties of solids including stress strain relationships Young’s modulus bulk modulus and shear modulus. It explains elasticity Hooke’s law factors influencing elasticity and practical applications. These concepts are essential for understanding material behavior and designing structures capable of withstanding forces in engineering and construction.
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The breaking tension of a wire is proportional to its cross-sectional area. It can be determined using the formula:
A = (π × d²) / 4
Step 1: Determine the areas
First wire (diameter = 1 mm):
A₁ = (π × 1²) / 4 = π / 4
Second wire (diameter = 2 mm):
A₂ = (π × 2²) / 4 = 4π / 4 = π
The area of the second wire is **4 times** the area of the first wire.
Step 2: Calculate the breaking tension
Breaking tension is proportional to the area.
For the first wire:
T₁ = 1000 N
For the second wire:
T₂ = 4 × T₁ = 4 × 1000 = 4000 N
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